1 solutions
-
1
废话不多说直接上代码
#include<bits/stdc++.h> using namespace std; int main(){ long long a,s,d;cin>>a>>s>>d; long long max1=a,min1=a; max1=max(max1,s);min1=min(min1,s); max1=max(max1,d);min1=min(min1,d); cout<<a+s+d-max1-min1; return 0; }
题目传送门 ☜戳亿下
不喜勿喷小雪参
- 1
Information
- ID
- 4908
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 9
- Tags
- (None)
- # Submissions
- 182
- Accepted
- 14
- Uploaded By