1 solutions

  • 0
    @ 2025-7-14 17:19:51

    #include using namespace std; int a[1000005],n,x; int main() { cin>>n; a[1]=1; a[2]=1; for(int i=3;i<=1000000;i++){ a[i]=(a[i-1]+a[i-2])%1000; } for(int j=1;j<=n;j++){ cin>>x; cout<<a[x]<<endl } return 0; }

    Information

    ID
    330
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    # Submissions
    6
    Accepted
    1
    Uploaded By